intersect L

This is an interesting configuration and the problem at hand gives the opportunity to list some of its properties.

(1) The circle c' through the center A of the given circle c and points {K,L} has its center P on the line AH.

(2) The other intersection points {Q,R} of the tangents {HL,HK} with circle c' define line QR symmetric to L

(3) The quadrangle LRKQ inscribed in c' is an isosceles trapezium.

(4) Points (A,M,O,H) = -1 define a harmonic division. Here M is the diametral of A and O the intersection of {L

(5) Point M, defined above, is an excenter of triangle ALK.

(6) Points (A,N,C,F) = -1 define also a harmonic division, where N is the other intersection point with c' of AC and F is the intersection of {AC, L

(1) is seen by drawing first the medial lines of segments AL, AK which meet at P and define there the circumcenter of ALK. Their parallels from {L,K}

respectively meet at the diametral M of A on the circumcircle c' of ALK. Since they are orthogonal to the bisectors of triangle HLK they are external bisectors

of its angles and define an excenter of triangle HLK.

(2), (3), (5) are immediate consequences.

(4) follows from the standard way to construct the polar of a point H with respect to a circle c' (see Polar2.html ).

(6) follows from (4) and the parallelity of lines {L

The initial claim is a consequence of (6). This claim is also equivalent to the orthogonality of circle c' to the circle with diameter FC.

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