f(t) = (at+b)/(ct

The set of points S={f(t)(

Inversely, every conic passing through the origin of coordinates and every set of two independent vectors {

This has been proved in ConicCharacterization.html . If the denominator has no or one real root, then the corresponding conic is respectively an

In the first case, absorbing some multipliers into vectors (

In the second case set simply c=0, thus obtaining f(t) = (t-a)/(t-b)

There is a degeneration possible when c=0, b=a, in which case, f(t) = 1/(t-a).

Then set S coincides with the set of points of the line x-ay=1 whose direction is that of the tangent at O and passes through

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