[alogo] Four Euler Circles

Consider a quadrangle A1A2A3A4 and its four "partial" triangles defined through its diagonals: A1A2A3, A2A3A4, ... etc. The Euler circles of these four triangles have a common point (C).

[0_0] [0_1]
[1_0] [1_1]
[2_0] [2_1]

Indeed, consider the "opposite" Euler circles c1, c2 passing through the middles E, F, G and D, B, G of the sides and the diagonal A1A3. Measure the angles at their second intersection point C: angle(GCD) = π-angle(GBD) = angle(A3DB) = angle(A3GB). Analogously angle(FCG) = angle(A3GE). Thus angle(FCD) = angle(FA3D) = angle(FHD) and the third Euler circle c3, passing through F, H, D passes also through C. Analogously the fourth circle passes also through C.
The theorem is intimately related to the problem of constructing a rectangular hyperbola passing through four non-orthocentric points discussed in the file RectHypeThroughFourPts.html .

See Also

Euler.html
EulerCircleProperty.html
HyperbolaRectangular.html
OrthoRectangular.html
RectangularAsProp.html
RectHyperbola.html
RectHypeCircumscribed.html
RectHypeThroughFourPts.html

Return to Gallery


Produced with EucliDraw©