The construction follows the recipe exposed in Pascal2.html . From the given data we determine first the intersection point H of (t) with BC. Then draw an arbitrary line DE through D intersecting AB at F. In order for E to be on the conic, the intersection point G of AD and CE must be collinear with F and H. Then the line p containing {F,G,H} will be the one whose existence is guaranteed from the theorem of Pascal.

Thus, G is determined on FH by intersecting it with AD and E is found as intersection of GC and FD. This reduces the problem to the one of finding a conic through the five points {A,B,C,D,E}.

DesarguesInvolution.html

FourPtsAndTangent.html

HomographicRelation.html

HomographicRelationExample.html

InvolutionBasic.html

InvolutionBasic2.html

Pascal.html

Pascal2.html

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