Given two triangles ABC and A'B'C' one pivot of inscription of A'B'C' in ABC is a point P, such that its pedal triangle with respect to ABC is similar to A'B'C'.
The basic properties of pivots are examined in the file Pivot.html . Here, fixing the angles of the triangles I examine the set of all pivots of A'B'C' relative to ABC. From corresponding properties of pedals (see references below) we know that the pedal of a point is similar to the pedals of the inverses of this point with respect to the Apollonian circles and also with respect to the circumcircle. These four inversions generate a finite group of 12 elements and the pivots of a definite couple of triangles builds an orbit of this group.
The group prototype G0, to which the general group G we are interested in is isomorphic, is the one generated by two reflections {R1, R2} on two lines respectively {e1, e2} making an angle of 60 degrees, and one inversion F with respect to a circle (c) centered at the intersection of these two lines as in the following figure.
Group G0 has 12 elements which are the three generators {R1, R2, F} the identity and the following eight: (i) The reflection R3 = R2R1R2 on the line e3 resulting by reflecting e1 on e2, (ii) the two rotations V1 = R2*R1, V2 = V12, (iii) and the six maps {F, FR1, FR2, FR3, FV1, FV2}.
This group has the sector AOB between lines {e1, e2} and the circle (c) as fundamental domain i.e. every orbit G0x = {g1x, ..., g12x} of the group, for x arbitrary point in the plane, meets this domain in exactly one point. Points inside the domain have orbits of exactly 12 points whereas points on the boundary have orbits with fewer than 12 points. More precisely points on the open arcs {OA, OB, AB} have orbits with 6 points, points {A,B} have orbits of 3 points and point O has an orbit of two points, which are O and the point at infinity I.
Given a triangle ABC there is a group G of twelve elements generated by the inversions on its Apollonian circles and also on its circumcircle. This group is isomorphic to the group G0 of the previous section through conjugation with a Moebius transformation H. H is defined by the requirement to map the vertices of an equilateral A0B0C0 correspondingly to the vertices of the triangle ABC.
H maps the symmetry axes of the equilateral to the Apollonian circles and the circumcircle of it to the circumcircle of ABC. Point O is maps via H to the first isodynamic point J of triangle ABC. Every element F of the group G is conjugate by H to some element F0 of the group G0 i.e. F = HF0H-1. The orbits Gy of a point y under G are images H(Gx) of orbits of the corresponding point x which maps to y(= H(x)). These facts are proved in the file Moebius.html . There it is also proved that the circles centered at O map via H to the circle bundle generated by the circumcircle and the Brocard circle of ABC, hence the orbits of y by G are by six on two circles of this bundle which are inverse with respect to the circumcircle.
By the analysis made here and in Pivots.html the pivots of inscription of a triangle A'B'C' into ABC are orbits Gy of the group G. Hence they contain 12 points if y is in the fundamental domain of the group which is the image of the fundamental domain of G0 under H. Thus there is in general a set of 12 pivots of inscription of A'B'C' into ABC. But if y is on the circumcircle arc CC' then the pedal triangle is degenerate (a Simson line), whereas if y is on the open arcs {JC, JC'} there are six pivots. This case is characteristic for pivots having pedals isosceli. Last case is when y coincides with J. In this case there are two pivots coinciding with the two isodynamic points. The corresponding pedal triangles are equilateral. A picture of the six pivots lying inside the circumcircle of the triangle can be viewed in Pivots.html .