The problem admits either two solutions or no solution at all. Since a triangle whose sides are tangent to a rectangular hyperbola must be obtuse-angled, the problem has solutions only if all partial triangles formed out of the four given points are obtuse-angled.

By partial triangles I mean the four triangles formed by selecting three sides of q. The picture below shows such a case where two hyperbolas exist. In addition it shows the tangent to the four sides parabola, which is always uniquely determined by q.

When the existence condition, described above, is valid, the crucial fact is that the conjugate circles of the four partial triangles are all members of a circle bundle of intersecting type. The two common points O

A case where the construction of tangent hyperbolas is impossible is shown in RectHypeImpossible.html .

EulerCircleProperty.html

FourEulerCircles.html

HyperbolaRectangular.html

Miquel_Point.html

NinePointsConic.html

OrthoRectangular.html

RectHypeCircumscribed.html

RectHypeImpossible.html

RectHyperbolaTriaInscribed.html

RectHypeThroughFourPts.html

Tangent4Lines.html

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